QScopedValueRollback: make constructor explicit

I'm not even sure whether you could implicitly
convert a T& into a QScopedValueRollback<T>,
seeing as the constructor takes a non-const
reference, but it looks wrong without explicit
and

  QObject o = new QObject(parent);

also won't compile even with implicit QObject(QObject*)
under a conformant compiler because of the disabled
copy constructor, and we still make QObject(QObject*)
explicit, so add it here, too.

Change-Id: I722a6e8431644e450fe2b401ccfb707a8e982380
Reviewed-by: Olivier Goffart <ogoffart@woboq.com>
Reviewed-by: Lars Knoll <lars.knoll@nokia.com>
Reviewed-by: Shane Kearns <shane.kearns@accenture.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/corelib/tools/qscopedvaluerollback.h b/src/corelib/tools/qscopedvaluerollback.h
index 23d2d9eda0..d53cabd315 100644
--- a/src/corelib/tools/qscopedvaluerollback.h
+++ b/src/corelib/tools/qscopedvaluerollback.h
@@ -51,7 +51,7 @@ template <typename T>
 class QScopedValueRollback
 {
 public:
-    QScopedValueRollback(T &var) :
+    explicit QScopedValueRollback(T &var) :
         varRef(var)
     {
         oldValue = varRef;