Add assignment operator for QJsonValueRef

The implicit cast to QJsonValue was being ignored probably because the
compiler was generating a default QJsonValueRef assignment operator

Change-Id: I3a041595497308868dd7e4aab71027ce21bf8f0b
Reviewed-by: Denis Dzyubenko <denis.dzyubenko@nokia.com>
Reviewed-by: Lars Knoll <lars.knoll@nokia.com>

2 files changed, 11 insertions, 0 deletions

diff --git a/src/corelib/json/qjsonvalue.cpp b/src/corelib/json/qjsonvalue.cpp
index 3be7089049..7459524fc9 100644
--- a/src/corelib/json/qjsonvalue.cpp
+++ b/src/corelib/json/qjsonvalue.cpp
@@ -548,6 +548,16 @@ QJsonValueRef &QJsonValueRef::operator =(const QJsonValue &val)
     return *this;
 }
 
+QJsonValueRef &QJsonValueRef::operator =(const QJsonValueRef &ref)
+{
+    if (is_object)
+        o->setValueAt(index, ref);
+    else
+        a->replace(index, ref);
+
+    return *this;
+}
+
 QJsonArray QJsonValueRef::toArray() const
 {
     return toValue().toArray();
diff --git a/src/corelib/json/qjsonvalue.h b/src/corelib/json/qjsonvalue.h
index 386bee25a4..9d4ad1d108 100644
--- a/src/corelib/json/qjsonvalue.h
+++ b/src/corelib/json/qjsonvalue.h
@@ -147,6 +147,7 @@ public:
 
     inline operator QJsonValue() const { return toValue(); }
     QJsonValueRef &operator = (const QJsonValue &val);
+    QJsonValueRef &operator = (const QJsonValueRef &val);
 
     inline QJsonValue::Type type() const { return toValue().type(); }
     inline bool isNull() const { return type() == QJsonValue::Null; }