Add QInputDevice::availableVirtualGeometry()

This property tells what part of the virtual desktop the input device
can access.

This is not a one-to-one mapping with a QScreen, because a Wacom tablet
might be configured to access a whole desktop, a whole screen, or an
area corresponding to the drawing area of one window; a mouse normally
can access the whole desktop (so QScreen::virtualGeometry() would be
identical to QInputDevice::availableVirtualGeometry()); a touchscreen
normally is mapped to one screen but could be mapped differently; etc.
It's possible to find the intersection of the rectangular area with the
screen(s) that it overlaps, though.

Task-number: QTBUG-78839
Change-Id: I9040e20fb5a3dec8a9a0dd827735826c4c1eea38
Reviewed-by: Jan Arve Sæther <jan-arve.saether@qt.io>

1 files changed, 5 insertions, 0 deletions

diff --git a/src/gui/kernel/qinputdevice.h b/src/gui/kernel/qinputdevice.h
index 5bff29f897..aa6b3aaf7c 100644
--- a/src/gui/kernel/qinputdevice.h
+++ b/src/gui/kernel/qinputdevice.h
@@ -58,6 +58,7 @@ class Q_GUI_EXPORT QInputDevice : public QObject
     Q_PROPERTY(Capabilities capabilities READ capabilities CONSTANT)
     Q_PROPERTY(qint64 id READ id CONSTANT)
     Q_PROPERTY(QString seatName READ seatName CONSTANT)
+    Q_PROPERTY(QRect availableVirtualGeometry READ availableVirtualGeometry NOTIFY availableVirtualGeometryChanged)
 
 public:
     enum class DeviceType : qint16 {
@@ -106,12 +107,16 @@ public:
     bool hasCapability(Capability cap) const;
     qint64 id() const;
     QString seatName() const;
+    QRect availableVirtualGeometry() const;
 
     static QList<const QInputDevice *> devices();
     static const QInputDevice *primaryKeyboard(const QString& seatName = QString());
 
     bool operator==(const QInputDevice &other) const;
 
+Q_SIGNALS:
+    void availableVirtualGeometryChanged(QRect area);
+
 protected:
     QInputDevice(QInputDevicePrivate &d, QObject *parent = nullptr);