iOS: Check if window was active on setVisible(false) through native APIs

When a QWindow is closed and destroyed it resets QGuiApp::focus_window
before calling setVisible(false) on the platform window, so we don't
have the needed information anymore to check if the window we are
hiding was the focus-window. To work around this we use the native
state instead, which should still be valid if the window was the
focus window.

Change-Id: I98057e6393411471f03668e3e5ce544f6b49c01d
Reviewed-by: Richard Moe Gustavsen <richard.gustavsen@theqtcompany.com>
Reviewed-by: Tor Arne Vestbø <tor.arne.vestbo@theqtcompany.com>

1 files changed, 17 insertions, 0 deletions

diff --git a/src/plugins/platforms/ios/quiview.mm b/src/plugins/platforms/ios/quiview.mm
index a56db1d6f5..8be3515cb5 100644
--- a/src/plugins/platforms/ios/quiview.mm
+++ b/src/plugins/platforms/ios/quiview.mm
@@ -261,6 +261,23 @@
     return YES;
 }
 
+- (BOOL)isActiveWindow
+{
+    // Normally this is determined exclusivly by being firstResponder, but
+    // since we employ a separate first responder for text input we need to
+    // handle both cases as this view being the active Qt window.
+
+    if ([self isFirstResponder])
+        return YES;
+
+    UIResponder *firstResponder = [UIResponder currentFirstResponder];
+    if ([firstResponder isKindOfClass:[QIOSTextInputResponder class]]
+        && [firstResponder nextResponder] == self)
+        return YES;
+
+    return NO;
+}
+
 // -------------------------------------------------------------------------