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authorTimur Pocheptsov <timur.pocheptsov@qt.io>2021-12-30 09:06:10 +0100
committerTor Arne Vestbø <tor.arne.vestbo@qt.io>2022-01-05 04:16:43 +0000
commiteabaa8a08e647273978f5786729776213e326aca (patch)
treed58dee7ba3bc70e24a76ce2bb0bb0fdff03e5c28 /src/plugins/styles/mac/qmacstyle_mac.mm
parent9ea1f0f8b98fb5a65261c611bdfdc71b05673268 (diff)
QMacStyle: use the 'momentary push in' type for push buttons
In the past, we were using different hacks to emulate the 'default' button and a normal button (and them in a pressed/not pressed active/non-active states). In macOS 12 old trick stopped working and UI looks a bit different: non-default buttons never get accent color even if pressed. Instead of relying on a combination of 'push on-push off' type's states and highlight, we can use the 'momentary push in' (highlighted == YES gives an impression of a pressed button) + setting a key equivalent (thanks to Tor Arne for the hint) gives the desired 'default button' look. Pick-to: 6.2 6.3 5.15 Task-number: QTBUG-98483 Change-Id: If7d665d217420b7732b556d98d9e0313258ff93e Reviewed-by: Tor Arne Vestbø <tor.arne.vestbo@qt.io>
Diffstat (limited to 'src/plugins/styles/mac/qmacstyle_mac.mm')
-rw-r--r--src/plugins/styles/mac/qmacstyle_mac.mm30
1 files changed, 22 insertions, 8 deletions
diff --git a/src/plugins/styles/mac/qmacstyle_mac.mm b/src/plugins/styles/mac/qmacstyle_mac.mm
index f8f2d1d0ef..9d57248673 100644
--- a/src/plugins/styles/mac/qmacstyle_mac.mm
+++ b/src/plugins/styles/mac/qmacstyle_mac.mm
@@ -1689,7 +1689,7 @@ bool QMacStylePrivate::CocoaControl::getCocoaButtonTypeAndBezelStyle(NSButtonTyp
*bezelStyle = NSBezelStyleShadowlessSquare;
break;
case Button_PushButton:
- *buttonType = NSButtonTypePushOnPushOff;
+ *buttonType = NSButtonTypeMomentaryPushIn;
*bezelStyle = NSBezelStyleRounded;
break;
default:
@@ -3716,8 +3716,16 @@ void QMacStyle::drawControl(ControlElement ce, const QStyleOption *opt, QPainter
pb.frame = frameRect.toCGRect();
pb.enabled = isEnabled;
+
+ // With the 'momentary push in' type this gives an impression of a
+ // button in a 'pressed' state (the 'momentary push in' does
+ // not show its state otherwise):
[pb highlight:isPressed];
- pb.state = isHighlighted && !isPressed ? NSControlStateValueOn : NSControlStateValueOff;
+
+ // For default/checked button this will give the required
+ // button accent color:
+ pb.keyEquivalent = isHighlighted ? @"\r" : @"";
+
d->drawNSViewInRect(pb, frameRect, p, ^(CGContextRef, const CGRect &r) {
[pb.cell drawBezelWithFrame:r inView:pb.superview];
});
@@ -3759,6 +3767,8 @@ void QMacStyle::drawControl(ControlElement ce, const QStyleOption *opt, QPainter
const bool hasText = !btn.text.isEmpty();
const bool isActive = btn.state & State_Active;
const bool isPressed = btn.state & State_Sunken;
+ const bool isDefault = (btn.features & QStyleOptionButton::DefaultButton && !d->autoDefaultButton)
+ || d->autoDefaultButton == btn.styleObject;
// cocoaControlType evaluates the type based on the control's geometry, not on the
// label's geometry
@@ -3769,12 +3779,16 @@ void QMacStyle::drawControl(ControlElement ce, const QStyleOption *opt, QPainter
btn.rect = oldRect;
if (!hasMenu && ct != QMacStylePrivate::Button_SquareButton) {
- if (isPressed
- || (isActive && isEnabled
- && ((btn.state & State_On)
- || ((btn.features & QStyleOptionButton::DefaultButton) && !d->autoDefaultButton)
- || d->autoDefaultButton == btn.styleObject)))
- btn.palette.setColor(QPalette::ButtonText, Qt::white);
+ if (isPressed || (isActive && isEnabled && ((btn.state & State_On) || isDefault)))
+ btn.palette.setColor(QPalette::ButtonText, Qt::white);
+ }
+
+ if (!isDarkMode() && QOperatingSystemVersion::current() > QOperatingSystemVersion::MacOSBigSur) {
+ if (!isDefault && !(btn.state & State_On)) {
+ // On macOS 12 it's a gray button, white text color (if set in the
+ // previous statement) would be almost invisible.
+ btn.palette.setColor(QPalette::ButtonText, Qt::black);
+ }
}
if ((!hasIcon && !hasMenu) || (hasIcon && !hasText)) {