Call raise on the window that contains the widget and not the widget

When the mouse is clicked on the widget in a window while a popup is
visible then it should raise just the window and not the widget inside it.
If the widget is in a stacked layout then calling raise() on it can cause
it to appear on top so avoid this by calling raise() directly on the
window.

Task-number: QTBUG-52670
Change-Id: Idd287c6cc7038c57e14e92f4a3e1c50985925684
Reviewed-by: Friedemann Kleint <Friedemann.Kleint@qt.io>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/widgets/kernel/qwidgetwindow.cpp b/src/widgets/kernel/qwidgetwindow.cpp
index 95f63025fb..40c488857e 100644
--- a/src/widgets/kernel/qwidgetwindow.cpp
+++ b/src/widgets/kernel/qwidgetwindow.cpp
@@ -529,7 +529,7 @@ void QWidgetWindow::handleMouseEvent(QMouseEvent *event)
                     // activate window of the widget under mouse pointer
                     if (!w->isActiveWindow()) {
                         w->activateWindow();
-                        w->raise();
+                        w->window()->raise();
                     }
 
                     QWindow *win = w->windowHandle();