Fix QString::operator=(QLatin1String) for substrings

QLatin1String now has a constructor that takes explicit length, which
makes it possible to create a QLatin1String that isn't null-terminated.
Made QString::operator=(QLatin1String) work in that case.

Change-Id: Ie77eabd2f8f036531d67cd8051a7b6305b386ccf
Reviewed-by: Lars Knoll <lars.knoll@nokia.com>

1 files changed, 23 insertions, 0 deletions

diff --git a/tests/auto/corelib/tools/qstring/tst_qstring.cpp b/tests/auto/corelib/tools/qstring/tst_qstring.cpp
index 781377f574..dae1dc45ba 100644
--- a/tests/auto/corelib/tools/qstring/tst_qstring.cpp
+++ b/tests/auto/corelib/tools/qstring/tst_qstring.cpp
@@ -224,6 +224,7 @@ private slots:
     void operatorGreaterWithQLatin1String();
     void compareQLatin1Strings();
     void fromQLatin1StringWithLength();
+    void assignQLatin1String();
 };
 
 typedef QList<int> IntList;
@@ -5286,6 +5287,28 @@ void tst_QString::fromQLatin1StringWithLength()
     QCOMPARE(foo, QString::fromLatin1("foo"));
 }
 
+void tst_QString::assignQLatin1String()
+{
+    QString empty = QLatin1String("");
+    QVERIFY(empty.isEmpty());
+    QVERIFY(!empty.isNull());
+
+    QString null = QLatin1String(0);
+    QVERIFY(null.isEmpty());
+    QVERIFY(null.isNull());
+
+    QLatin1String latin1foo("foo");
+    QString foo = latin1foo;
+    QCOMPARE(foo.size(), latin1foo.size());
+    QCOMPARE(foo, QString::fromLatin1("foo"));
+
+    QLatin1String latin1subfoo("foobar", 3);
+    foo = latin1subfoo;
+    QCOMPARE(foo.size(), latin1subfoo.size());
+    QCOMPARE(foo, QString::fromLatin1("foo"));
+
+}
+
 QTEST_APPLESS_MAIN(tst_QString)
 
 #include "tst_qstring.moc"