From 8481500f639e3d5e2259db57847a2e7068e30650 Mon Sep 17 00:00:00 2001 From: Samuel Gaist Date: Wed, 17 Jun 2015 11:07:14 +0200 Subject: Improve QString doc when using non-spaced numbered place marker Currently when a developer uses a string like QString("%1%3%2").arg(x).arg(y).arg(z) he can be bitten by the sequential replacement done by QString. Adding an example with a little explanation should help future Qt user avoid generating buggy strings. Task-number: QTBUG-44044 Change-Id: I81e20af8d9fb2a07e12ec61dcd5bb4544d863777 Reviewed-by: Sze Howe Koh --- src/corelib/doc/snippets/qstring/main.cpp | 13 +++++++++++++ 1 file changed, 13 insertions(+) (limited to 'src/corelib/doc/snippets/qstring/main.cpp') diff --git a/src/corelib/doc/snippets/qstring/main.cpp b/src/corelib/doc/snippets/qstring/main.cpp index 4687d52e54..e03e705a0b 100644 --- a/src/corelib/doc/snippets/qstring/main.cpp +++ b/src/corelib/doc/snippets/qstring/main.cpp @@ -261,6 +261,19 @@ void Widget::argFunction() str.arg("%1f").arg("Hello"); // returns "Hellof %2" //! [13] + //! [97] + str = "%1%3%2"; + str.arg("Hello").arg(20).arg(50); // returns "Hello500" + + str = "%1%2%3"; + str.arg("Hello").arg(50).arg(20); // returns "Hello5020" + //! [97] + + //! [98] + str = "%1%2%3"; + str.arg("Hello", QString::number(20), QString::number(50)); // returns "Hello5020" + //! [98] + //! [14] str = QString("Decimal 63 is %1 in hexadecimal") .arg(63, 0, 16); -- cgit v1.2.3