From 10a88b8149e7699b08871a8a62892ac0f39b54f2 Mon Sep 17 00:00:00 2001
From: Allan Sandfeld Jensen <allan.jensen@qt.io>
Date: Thu, 26 Jul 2018 17:14:07 +0200
Subject: Add debug output for single enum flags

They have a separate type that we can't recognize directly, but we
can check if we can recognize the QFlags<T> form, though we have to
add a lot of template-conditions to avoid triggering QFlags static
asserts.

Change-Id: I00853682c5376dd3cc411ff151f47bce2389e277
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>
Reviewed-by: Olivier Goffart (Woboq GmbH) <ogoffart@woboq.com>
---
 src/corelib/io/qdebug.h | 13 +++++++++++++
 1 file changed, 13 insertions(+)

(limited to 'src/corelib/io/qdebug.h')

diff --git a/src/corelib/io/qdebug.h b/src/corelib/io/qdebug.h
index ee8ef679a9..ae1869f89e 100644
--- a/src/corelib/io/qdebug.h
+++ b/src/corelib/io/qdebug.h
@@ -376,6 +376,19 @@ operator<<(QDebug dbg, T value)
     return qt_QMetaEnum_debugOperator(dbg, typename QFlags<T>::Int(value), obj, name);
 }
 
+template<typename T,
+         typename A = typename std::enable_if<std::is_enum<T>::value, void>::type,
+         typename B = typename std::enable_if<sizeof(T) <= sizeof(int), void>::type,
+         typename C = typename std::enable_if<!QtPrivate::IsQEnumHelper<T>::Value, void>::type,
+         typename D = typename std::enable_if<QtPrivate::IsQEnumHelper<QFlags<T>>::Value, void>::type>
+inline QDebug operator<<(QDebug dbg, T value)
+{
+    typedef QFlags<T> FlagsT;
+    const QMetaObject *obj = qt_getEnumMetaObject(FlagsT());
+    const char *name = qt_getEnumName(FlagsT());
+    return qt_QMetaEnum_debugOperator(dbg, typename FlagsT::Int(value), obj, name);
+}
+
 template <class T>
 inline typename std::enable_if<
     QtPrivate::IsQEnumHelper<T>::Value || QtPrivate::IsQEnumHelper<QFlags<T> >::Value,
-- 
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