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authorTimur Pocheptsov <timur.pocheptsov@qt.io>2017-06-29 14:08:42 +0200
committerAlex Blasche <alexander.blasche@qt.io>2017-06-29 12:38:52 +0000
commit29b98ef4a4a34497cfcb6091554809673024340e (patch)
tree7ad9109da5aa1ba3d187bae05e4d1748d390466a
parent0148c476bbc407c00d40f65f9e166226043ec5cf (diff)
Device discovery (CoreBluetooth): report duplicates in case LE scan has timeout 0
If we have a never-ending LE scan, we should report even complete duplicates. The original bug-report has a scenario with a long-running application, that records a data from BTLE scales once a day. Task-number: QTBUG-57847 Change-Id: If5e4828f119d5f4e4418cfe60fa518b583210a14 Reviewed-by: Alex Blasche <alexander.blasche@qt.io>
-rw-r--r--src/bluetooth/qbluetoothdevicediscoveryagent_osx.mm2
1 files changed, 1 insertions, 1 deletions
diff --git a/src/bluetooth/qbluetoothdevicediscoveryagent_osx.mm b/src/bluetooth/qbluetoothdevicediscoveryagent_osx.mm
index b308f7cc..9e3f6a57 100644
--- a/src/bluetooth/qbluetoothdevicediscoveryagent_osx.mm
+++ b/src/bluetooth/qbluetoothdevicediscoveryagent_osx.mm
@@ -525,7 +525,7 @@ void QBluetoothDeviceDiscoveryAgentPrivate::deviceFound(const QBluetoothDeviceIn
for (int i = 0, e = discoveredDevices.size(); i < e; ++i) {
if (isLE ? discoveredDevices[i].deviceUuid() == newDeviceInfo.deviceUuid():
discoveredDevices[i].address() == newDeviceInfo.address()) {
- if (discoveredDevices[i] == newDeviceInfo)
+ if (discoveredDevices[i] == newDeviceInfo && (!isLE || lowEnergySearchTimeout > 0))
return;
discoveredDevices.replace(i, newDeviceInfo);