QQmlListModel: use alignof for alignment

Change-Id: I1dac3e33289516ec677d6db0d8d7cf1e02addc16
Reviewed-by: Lars Knoll <lars.knoll@qt.io>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/qmlmodels/qqmllistmodel.cpp b/src/qmlmodels/qqmllistmodel.cpp
index 921b4d41f2..a0f19ce52a 100644
--- a/src/qmlmodels/qqmllistmodel.cpp
+++ b/src/qmlmodels/qqmllistmodel.cpp
@@ -130,7 +130,7 @@ const ListLayout::Role &ListLayout::getRoleOrCreate(QV4::String *key, Role::Data
 const ListLayout::Role &ListLayout::createRole(const QString &key, ListLayout::Role::DataType type)
 {
     const int dataSizes[] = { sizeof(StringOrTranslation), sizeof(double), sizeof(bool), sizeof(ListModel *), sizeof(QPointer<QObject>), sizeof(QVariantMap), sizeof(QDateTime), sizeof(QUrl), sizeof(QJSValue) };
-    const int dataAlignments[] = { sizeof(StringOrTranslation), sizeof(double), sizeof(bool), sizeof(ListModel *), sizeof(QObject *), sizeof(QVariantMap), sizeof(QDateTime), sizeof(QUrl), sizeof(QJSValue) };
+    const int dataAlignments[] = { alignof(StringOrTranslation), alignof(double), alignof(bool), alignof(ListModel *), alignof(QObject *), alignof(QVariantMap), alignof(QDateTime), alignof(QUrl), alignof(QJSValue) };
 
     Role *r = new Role;
     r->name = key;