QQuickDial: account for when the wheel event is inverted

On macOS, the vertical scrolling with the wheel may be inverted, so we
need to account for this when getting the y angle.

Change-Id: Ia0f59beba905beff7b0cf12271a654c721bd5179
Reviewed-by: Andy Shaw <andy.shaw@qt.io>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/quicktemplates2/qquickdial.cpp b/src/quicktemplates2/qquickdial.cpp
index 2b9f83a4..04f4eda5 100644
--- a/src/quicktemplates2/qquickdial.cpp
+++ b/src/quicktemplates2/qquickdial.cpp
@@ -613,7 +613,7 @@ void QQuickDial::wheelEvent(QWheelEvent *event)
     if (d->wheelEnabled) {
         const qreal oldValue = d->value;
         const QPointF angle = event->angleDelta();
-        const qreal delta = (qFuzzyIsNull(angle.y()) ? angle.x() : angle.y()) / QWheelEvent::DefaultDeltasPerStep;
+        const qreal delta = (qFuzzyIsNull(angle.y()) ? angle.x() : (event->inverted() ? -angle.y() : angle.y())) / QWheelEvent::DefaultDeltasPerStep;
         const qreal step = qFuzzyIsNull(d->stepSize) ? 0.1 : d->stepSize;
         setValue(oldValue + step * delta);
         event->setAccepted(!qFuzzyCompare(d->value, oldValue));