Update QtConcurrent docs and examples for reductor object usage

After 6ebe3d0f0806069f906522dfe9b81baa3f3478de users don't have to
specify the result type when using functors for as a reductor.

Task-number: QTBUG-88448
Change-Id: I065fed11c1a66833ba0aac3d18e7ff0545247be1
Reviewed-by: Mårten Nordheim <marten.nordheim@qt.io>

1 files changed, 4 insertions, 6 deletions

diff --git a/src/concurrent/doc/snippets/code/src_concurrent_qtconcurrentfilter.cpp b/src/concurrent/doc/snippets/code/src_concurrent_qtconcurrentfilter.cpp
index 0e0f414b13..b9ff35c798 100644
--- a/src/concurrent/doc/snippets/code/src_concurrent_qtconcurrentfilter.cpp
+++ b/src/concurrent/doc/snippets/code/src_concurrent_qtconcurrentfilter.cpp
@@ -177,9 +177,7 @@ struct StringTransform
 };
 
 QFuture<QString> fooString =
-  QtConcurrent::filteredReduced<QString>(strings,
-                                         StartsWith(QLatin1String("Foo")),
-                                         StringTransform());
+        QtConcurrent::filteredReduced(strings, StartsWith(QLatin1String("Foo")), StringTransform());
 //! [14]
 
 //! [15]
@@ -196,7 +194,7 @@ QList<int> results = future.results();
 
 // add up all even integers
 QList<int> list3 { 1, 2, 3, 4 };
-int sum = QtConcurrent::filteredReduced<int>(list3,
+QFuture<int> sum = QtConcurrent::filteredReduced(list3,
     [](int x) {
         return (x & 1) == 0;
     },
@@ -213,7 +211,7 @@ void intSumReduce(int &sum, int x)
 }
 
 QList<int> list { 1, 2, 3, 4 };
-int sum = QtConcurrent::filteredReduced(list,
+QFuture<int> sum = QtConcurrent::filteredReduced(list,
     [] (int x) {
         return (x & 1) == 0;
     },
@@ -228,7 +226,7 @@ bool keepEvenIntegers(int x)
 }
 
 QList<int> list { 1, 2, 3, 4 };
-int sum = QtConcurrent::filteredReduced<int>(list,
+QFuture<int> sum = QtConcurrent::filteredReduced(list,
     keepEvenIntegers,
     [](int &sum, int x) {
         sum += x;