QUrl: use partially-decoded data in toString and QUrl(QString)

This fixes round-trip bugs. People expect to be able to do
QUrl u(...); QString s = u.toString(); QUrl u2(s); and have u==u2.
This was not true for paths containing a '#', for instance, which would
be parsed back as a fragment. The solution is to make toString output
partially decoded data (more readable than toEncoded, but not decoded
to the point of changing the meaning, if parsing it back later as a
QUrl), and to make the QUrl constructor work with partially decoded data.

Change-Id: I013c01e8947d538435f3c20fc4ec57cd9ccbba6c
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>

0 files changed, 0 insertions, 0 deletions