Deprecate constructing QFlags from a pointer

This was used to support QFlags f = 0 initialization, but with 0 used
as a pointer literal now considered bad form, it had been changed many
places to QFlags f = nullptr, which is meaningless and confusing.

Change-Id: I4bc592151c255dc5cab1a232615caecc520f02e8
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>

1 files changed, 2 insertions, 2 deletions

diff --git a/src/gui/painting/qplatformbackingstore.cpp b/src/gui/painting/qplatformbackingstore.cpp
index 45e90bd99b..0ecb4390e9 100644
--- a/src/gui/painting/qplatformbackingstore.cpp
+++ b/src/gui/painting/qplatformbackingstore.cpp
@@ -427,7 +427,7 @@ void QPlatformBackingStore::composeAndFlush(QWindow *window, const QRegion &regi
             origin = QOpenGLTextureBlitter::OriginBottomLeft;
         textureId = d_ptr->textureId;
     } else {
-        TextureFlags flags = 0;
+        TextureFlags flags;
         textureId = toTexture(deviceRegion(region, window, offset), &d_ptr->textureSize, &flags);
         d_ptr->needsSwizzle = (flags & TextureSwizzle) != 0;
         d_ptr->premultiplied = (flags & TexturePremultiplied) != 0;
@@ -534,7 +534,7 @@ GLuint QPlatformBackingStore::toTexture(const QRegion &dirtyRegion, QSize *textu
     GLuint pixelType = GL_UNSIGNED_BYTE;
 
     bool needsConversion = false;
-    *flags = 0;
+    *flags = { };
     switch (image.format()) {
     case QImage::Format_ARGB32_Premultiplied:
         *flags |= TexturePremultiplied;