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authorJiewen Wang <jiewen.wang@logicpd.com>2012-05-25 08:13:11 -0400
committerQt by Nokia <qt-info@nokia.com>2012-05-25 21:41:42 +0200
commit7381328bcc37283be97eedddc24c46be1e38490e (patch)
tree321ad3bb9a7a2be89469feb408c355f714cff9a9 /src/widgets
parent2848395b50346b87e28e5bb0523ae1a0aff1d0fc (diff)
QStatusBar::showMessage will always take new timeout
There is a message check in QStatusBar::showMessage causing the call exits early if the new 'message' is the same as the current message. The check has been removed, and new timeout will always take effect. Unit test is added as well. Change-Id: I3a03c6842835824caba4adc37c3ed834952c4bb2 Task-Id: QTBUG-25492 Reviewed-by: Girish Ramakrishnan <girish.1.ramakrishnan@nokia.com>
Diffstat (limited to 'src/widgets')
-rw-r--r--src/widgets/widgets/qstatusbar.cpp2
1 files changed, 0 insertions, 2 deletions
diff --git a/src/widgets/widgets/qstatusbar.cpp b/src/widgets/widgets/qstatusbar.cpp
index 2b17d7fb83..4e6b273a3c 100644
--- a/src/widgets/widgets/qstatusbar.cpp
+++ b/src/widgets/widgets/qstatusbar.cpp
@@ -546,8 +546,6 @@ void QStatusBar::reformat()
void QStatusBar::showMessage(const QString &message, int timeout)
{
Q_D(QStatusBar);
- if (d->tempItem == message)
- return;
d->tempItem = message;