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// Copyright 2009 the Sputnik authors. All rights reserved.
// This code is governed by the BSD license found in the LICENSE file.
/*---
info: String.prototype.indexOf works properly
es5id: 15.5.4.7_A5_T6
description: Search substring from it`s position+1 in the string
---*/
var TEST_STRING = new String( " !\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~" );
//////////////////////////////////////////////////////////////////////////////
//CHECK#1
for (var k = 0, i = 0x0020; i < 0x007d; i++, k++ ) {
if (TEST_STRING.indexOf( (String.fromCharCode(i)+ String.fromCharCode(i+1)+ String.fromCharCode(i+2)), k+1 )!== -1) {
$ERROR('#'+(i-0x0020)+': TEST_STRING.indexOf( (String.fromCharCode('+i+')+ String.fromCharCode('+(i+1)+') + String.fromCharCode('+(i+2)+')), '+(k+1)+' )=== -1. Actual: '+TEST_STRING.indexOf( (String.fromCharCode(i)+ String.fromCharCode(i+1) + String.fromCharCode(i+2)), k+1 ));
}
}
//
//////////////////////////////////////////////////////////////////////////////
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