1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
|
// Copyright 2009 the Sputnik authors. All rights reserved.
// This code is governed by the BSD license found in the LICENSE file.
/**
* @name: S15.5.4.4_A4_T3;
* @section: 15.5.4.4;
* @assertion: If pos is a value of Number type that is an integer, then the result of x.charAt(pos) is equal to the result of x.substring(pos, pos+1);
* @description: Compare results of x.charAt(pos) and x.substring(pos, pos+1), wheb pos is bigger string length;
*/
// Converted for Test262 from original Sputnik source
ES5Harness.registerTest( {
id: "S15.5.4.4_A4_T3",
path: "TestCases/15_Native/15.5_String_Objects/15.5.4_Properties_of_the_String_Prototype_Object/15.5.4.4_String.prototype.charAt/S15.5.4.4_A4_T3.js",
assertion: "If pos is a value of Number type that is an integer, then the result of x.charAt(pos) is equal to the result of x.substring(pos, pos+1)",
description: "Compare results of x.charAt(pos) and x.substring(pos, pos+1), wheb pos is bigger string length",
test: function testcase() {
//////////////////////////////////////////////////////////////////////////////
//CHECK#1
for(var i=6; i<8; i++) {
if ("ABC\u0041\u0042\u0043".charAt(i) !== "\u0041\u0042\u0043ABC".substring(i, i+1)) {
$ERROR('#'+(i-5)+': "ABC\\u0041\\u0042\\u0043".charAt('+i+') === "\\u0041\\u0042\\u0043ABC".substring('+i+', '+(i+1)+'). Actual: "ABC\\u0041\\u0042\\u0043".charAt('+i+') ==='+("ABC\u0041\u0042\u0043".charAt(i)));
}
}
//
//////////////////////////////////////////////////////////////////////////////
}
});
|
