blob: 142483ab1a22e82af8cd1bdebaf0daf920e05d56 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
|
// Copyright 2009 the Sputnik authors. All rights reserved.
// This code is governed by the BSD license found in the LICENSE file.
/**
* @name: S15.5.4.7_A5_T4;
* @section: 15.5.4.7;
* @assertion: String.prototype.indexOf works properly;
* @description: Search substring from begin of string;
*/
// Converted for Test262 from original Sputnik source
ES5Harness.registerTest( {
id: "S15.5.4.7_A5_T4",
path: "TestCases/15_Native/15.5_String_Objects/15.5.4_Properties_of_the_String_Prototype_Object/15.5.4.7_String.prototype.indexOf/S15.5.4.7_A5_T4.js",
assertion: "String.prototype.indexOf works properly",
description: "Search substring from begin of string",
test: function testcase() {
var TEST_STRING = new String( " !\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~" );
//////////////////////////////////////////////////////////////////////////////
//CHECK#1
for (var k = 0, i = 0x0020; i < 0x007d; i++, k++ ) {
if (TEST_STRING.indexOf( (String.fromCharCode(i)+ String.fromCharCode(i+1) + String.fromCharCode(i+2)), 0 )!==k) {
$ERROR('#'+(i-0x0020)+': TEST_STRING.indexOf( (String.fromCharCode('+i+')+ String.fromCharCode('+(i+1)+') + String.fromCharCode('+(i+2)+')), 0 )==='+k+'. Actual: '+TEST_STRING.indexOf( (String.fromCharCode(i)+ String.fromCharCode(i+1) + String.fromCharCode(i+2)), 0 ));
}
}
//
//////////////////////////////////////////////////////////////////////////////
}
});
|