Make sensor possible to indicate it is no longer busy

The current implementation allowed sensor backend to only indicate
that it is busy, but not to tell when it was freed again. This commit
allows sensor backend to indicate also that it's busy state has cleared.

It is up to the sensor implementation to decide if it makes sense /
is possible to do that or not.

Pick-to: 6.2
Task-number: QTBUG-92513
Task-number: QTBUG-92505
Change-Id: Ied4857850e81346031fd83aa347d9955081118e8
Reviewed-by: Alex Blasche <alexander.blasche@qt.io>

1 files changed, 12 insertions, 6 deletions

diff --git a/src/sensors/qsensorbackend.cpp b/src/sensors/qsensorbackend.cpp
index 31e2e811..1e75644b 100644
--- a/src/sensors/qsensorbackend.cpp
+++ b/src/sensors/qsensorbackend.cpp
@@ -318,21 +318,27 @@ void QSensorBackend::sensorStopped()
 }
 
 /*!
-    Inform the front end that the sensor is busy.
-    This implicitly calls sensorStopped() and
-    is typically called from start().
+    Inform the front end of the sensor's busy state according
+    to the provided \a busy parameter.
+
+    If the sensor is set \e busy this implicitly calls sensorStopped().
+    Busy indication is typically done in start().
 
     Note that the front end must call QSensor::isBusy() to see if
     the sensor is busy. If the sensor has stopped due to an error
     the sensorError() function should be called to notify the class
     of the error condition.
 */
-void QSensorBackend::sensorBusy()
+void QSensorBackend::sensorBusy(bool busy)
 {
     Q_D(QSensorBackend);
     QSensorPrivate *sensorPrivate = d->m_sensor->d_func();
-    sensorPrivate->active = false;
-    sensorPrivate->busy = true;
+    if (sensorPrivate->busy == busy)
+        return;
+    if (busy)
+        sensorPrivate->active = false;
+    sensorPrivate->busy = busy;
+    emit d->m_sensor->busyChanged();
 }
 
 /*!