1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
|
#!/usr/bin/env python
#############################################################################
##
## Copyright (C) 2016 The Qt Company Ltd.
## Contact: https://www.qt.io/licensing/
##
## This file is part of the test suite of Qt for Python.
##
## $QT_BEGIN_LICENSE:GPL-EXCEPT$
## Commercial License Usage
## Licensees holding valid commercial Qt licenses may use this file in
## accordance with the commercial license agreement provided with the
## Software or, alternatively, in accordance with the terms contained in
## a written agreement between you and The Qt Company. For licensing terms
## and conditions see https://www.qt.io/terms-conditions. For further
## information use the contact form at https://www.qt.io/contact-us.
##
## GNU General Public License Usage
## Alternatively, this file may be used under the terms of the GNU
## General Public License version 3 as published by the Free Software
## Foundation with exceptions as appearing in the file LICENSE.GPL3-EXCEPT
## included in the packaging of this file. Please review the following
## information to ensure the GNU General Public License requirements will
## be met: https://www.gnu.org/licenses/gpl-3.0.html.
##
## $QT_END_LICENSE$
##
#############################################################################
import time,os
class TimeoutException(Exception):
def __init__(self, msg):
self.msg = msg
def __str__(self):
return repr(self.msg)
class ProcessTimer(object):
'''Timeout function for controlling a subprocess.Popen instance.
Naive implementation using busy loop, see later other means
of doing this.
'''
def __init__(self, proc, timeout):
self.proc = proc
self.timeout = timeout
def waitfor(self):
time_passed = 0
while(self.proc.poll() is None and time_passed < self.timeout):
time_passed = time_passed + 1
time.sleep(1)
if time_passed >= self.timeout:
raise TimeoutException("Timeout expired, possible deadlock")
if __name__ == "__main__":
#simple example
from subprocess import Popen
proc = Popen(['sleep','10'])
t = ProcessTimer(proc,5)
try:
t.waitfor()
except TimeoutException:
print "timeout - PID: %d" % (t.proc.pid)
#TODO: detect SO and kill accordingly
#Linux
os.kill(t.proc.pid, 9)
#Windows (not tested)
#subprocess.Popen("taskkill /F /T /PID %i"%handle.pid , shell=True)
print "exit code: %d" % (t.proc.poll())
|
