C++: Fix variable template parsing in expression

Fix parser to not fail on TemplateId without parentheses, for example:
int i = foo<int> + foo<char>;

This fixes std::pair structure parsing in MSVC headers and find Usages
to work with pair->first and pair->second.

Change-Id: Ic300ea99d44a749705430d5eb47b2744715af995
Reviewed-by: Christian Kandeler <christian.kandeler@qt.io>

1 files changed, 0 insertions, 6 deletions

diff --git a/src/libs/3rdparty/cplusplus/Parser.cpp b/src/libs/3rdparty/cplusplus/Parser.cpp
index 28dddc507e..3c509be00c 100644
--- a/src/libs/3rdparty/cplusplus/Parser.cpp
+++ b/src/libs/3rdparty/cplusplus/Parser.cpp
@@ -5066,12 +5066,6 @@ bool Parser::parseNameId(NameAST *&name)
     case T_CONST_CAST:
         rewind(start);
         return parseName(name, false);
-
-    default:
-        if (tok().isLiteral() || tok().isPunctuationOrOperator()) {
-            rewind(start);
-            return parseName(name, false);
-        }
     } // switch
 
     return true;