C++: Fix resolving of using in enclosing scope

Use-case:
namespace Ns {
namespace Nested {
struct Foo
{
    void func();
    int bar;
};
}
}

using namespace Ns::Nested;

namespace Ns
{
void Foo::func()
{
    bar; // bar not highlighted
}
}

Change-Id: I6e667d63eb40511d65532c4d6d317aa4028a87a4
Reviewed-by: Nikolai Kosjar <nikolai.kosjar@theqtcompany.com>

1 files changed, 23 insertions, 0 deletions

diff --git a/src/plugins/cpptools/cppcompletion_test.cpp b/src/plugins/cpptools/cppcompletion_test.cpp
index 3bf0904c65..c743e0ed7d 100644
--- a/src/plugins/cpptools/cppcompletion_test.cpp
+++ b/src/plugins/cpptools/cppcompletion_test.cpp
@@ -1551,6 +1551,29 @@ void CppToolsPlugin::test_completion_data()
             << QLatin1String("C")
             << QLatin1String("m"));
 
+    QTest::newRow("type_and_using_declaration: type in nested namespace and using in global") << _(
+            "namespace Ns {\n"
+            "namespace Nested {\n"
+            "struct Foo\n"
+            "{\n"
+            "    void func();\n"
+            "    int m_bar;\n"
+            "};\n"
+            "}\n"
+            "}\n"
+            "\n"
+            "using namespace Ns::Nested;\n"
+            "\n"
+            "namespace Ns\n"
+            "{\n"
+            "void Foo::func()\n"
+            "{\n"
+            "    @\n"
+            "}\n"
+            "}\n"
+        ) << _("m_") << (QStringList()
+            << QLatin1String("m_bar"));
+
     QTest::newRow("instantiate_template_with_anonymous_class") << _(
             "template <typename T>\n"
             "struct S\n"