Fix QString::toHtmlEscaped() for >2Gi character strings

More unfinished int → qsizetype porting.

Manual conflict resolutions:
  - _L1 → QLatin1String
  - but keep the QLatin1Char → u'' changes as a drive-by

Fixes: QTBUG-105104
Change-Id: I3470de31c476b3d7736661550916828e43546573
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>
Reviewed-by: Edward Welbourne <edward.welbourne@qt.io>
(cherry picked from commit c1991c63fc081a42ed3e6a28f82f395c54ef42a1)

1 files changed, 7 insertions, 7 deletions

diff --git a/src/corelib/text/qstring.cpp b/src/corelib/text/qstring.cpp
index 9005f3267a..b5d7839693 100644
--- a/src/corelib/text/qstring.cpp
+++ b/src/corelib/text/qstring.cpp
@@ -10730,19 +10730,19 @@ qsizetype QtPrivate::count(QStringView haystack, const QRegularExpression &re)
 QString QString::toHtmlEscaped() const
 {
     QString rich;
-    const int len = length();
+    const qsizetype len = length();
     rich.reserve(qsizetype(len * 1.1));
-    for (int i = 0; i < len; ++i) {
-        if (at(i) == QLatin1Char('<'))
+    for (QChar ch : *this) {
+        if (ch == u'<')
             rich += QLatin1String("&lt;");
-        else if (at(i) == QLatin1Char('>'))
+        else if (ch == u'>')
             rich += QLatin1String("&gt;");
-        else if (at(i) == QLatin1Char('&'))
+        else if (ch == u'&')
             rich += QLatin1String("&amp;");
-        else if (at(i) == QLatin1Char('"'))
+        else if (ch == u'"')
             rich += QLatin1String("&quot;");
         else
-            rich += at(i);
+            rich += ch;
     }
     rich.squeeze();
     return rich;